更新 function.py
Gitea Actions Challenge Test / Challenge-Actions (push) Successful in 11s

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2024-10-06 18:09:13 +08:00
parent 8e37f981e6
commit 55750be82d
+13 -20
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@@ -39,7 +39,7 @@ name = "吴俊煯"
# 这里写自己的代码实现
def classify0(inX, dataSet, labels,k=4):
def classify0(inX, dataSet, labels,k=8):
"""
KNN 分类算法。
@@ -52,25 +52,18 @@ def classify0(inX, dataSet, labels,k=4):
- int: 预测的分类标签。
"""
# 确保 k 不大于数据集的大小
k = min(k, dataSet.shape[0])
# 计算测试样本与每个训练样本之间的距离
diffMat = np.tile(inX, (dataSet.shape[0], 1)) - dataSet
sqDiffMat = diffMat ** 2
distances = np.sqrt(sqDiffMat.sum(axis=1))
# 对距离进行排序,并获取索引
sortedDistIndicies = distances.argsort()
# 选择距离最小的k个点
classCount = {}
for i in range(k):
voteIlabel = labels[sortedDistIndicies[i]]
classCount[voteIlabel] = classCount.get(voteIlabel, 0) + 1
# 多数投票
sortedClassCount = sorted(classCount.items(), key=lambda item: item[1], reverse=True)
return sortedClassCount[0][0]
# 计算数据集的协方差矩阵的逆
VI = np.linalg.inv(np.cov(dataset.T))
# 计算 inX 与数据集的差值
diff = dataSet -inX
# 使用矩阵运算计算马氏距离
distances =np.sqrt(np,sum(diff @ VI * diff,axis=1))
# 对距离排序,获取前 k 个最近的样本索引
sortedDistIndices=np.argsort(distances)
# 统计前 k 个样本的标签
classCount =np.bincount(labels[sortedDistIndices[:k]])
# 返回出现次数最多的标签
return np.argmax(classCount)
def load_data(file_path):