generated from LufsX/Challenge-kNN
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@@ -39,7 +39,7 @@ name = "吴俊煯"
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# 这里写自己的代码实现
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def classify0(inX, dataSet, labels,k=4):
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def classify0(inX, dataSet, labels,k=8):
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"""
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KNN 分类算法。
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@@ -52,25 +52,18 @@ def classify0(inX, dataSet, labels,k=4):
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- int: 预测的分类标签。
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"""
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# 确保 k 不大于数据集的大小
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k = min(k, dataSet.shape[0])
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# 计算测试样本与每个训练样本之间的距离
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diffMat = np.tile(inX, (dataSet.shape[0], 1)) - dataSet
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sqDiffMat = diffMat ** 2
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distances = np.sqrt(sqDiffMat.sum(axis=1))
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# 对距离进行排序,并获取索引
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sortedDistIndicies = distances.argsort()
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# 选择距离最小的k个点
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classCount = {}
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for i in range(k):
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voteIlabel = labels[sortedDistIndicies[i]]
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classCount[voteIlabel] = classCount.get(voteIlabel, 0) + 1
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# 多数投票
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sortedClassCount = sorted(classCount.items(), key=lambda item: item[1], reverse=True)
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return sortedClassCount[0][0]
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# 计算数据集的协方差矩阵的逆
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VI = np.linalg.inv(np.cov(dataset.T))
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# 计算 inX 与数据集的差值
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diff = dataSet -inX
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# 使用矩阵运算计算马氏距离
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distances =np.sqrt(np,sum(diff @ VI * diff,axis=1))
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# 对距离排序,获取前 k 个最近的样本索引
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sortedDistIndices=np.argsort(distances)
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# 统计前 k 个样本的标签
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classCount =np.bincount(labels[sortedDistIndices[:k]])
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# 返回出现次数最多的标签
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return np.argmax(classCount)
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def load_data(file_path):
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