更新 function.py
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This commit is contained in:
2024-10-31 15:09:37 +08:00
parent 54c6999863
commit 7eb48c19c8
+22 -20
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@@ -17,38 +17,50 @@ import numpy as np
- numpy: 2.1.1
"""
"""
请在这里填写学号和姓名,不填写即成绩无效。
"""
id = "202210423213"
name = "熊浩燃"
id = "202210423xxx"
name = "test_name"
# 这里写自己的代码实现
def sigmoid(z):
return 1 / (1 + np.exp(-z))
def train_logreg(X, y, learning_rate=0.01, iterations=1000):
def normalize(X):
""" 数据归一化 """
return (X - np.mean(X, axis=0)) / np.std(X, axis=0)
def train_logreg(X, y, learning_rate=0.01, iterations=1000, batch_size=32, lambda_=0.01):
"""
对率回归训练函数。
对率回归训练函数,包含批量梯度下降和L2正则化。
Args:
- X (numpy array): 特征数据。
- y (numpy array): 标签数据。
- learning_rate (float): 学习率。
- iterations (int): 迭代次数。
- batch_size (int): 每次更新的样本数。
- lambda_ (float): L2正则化项的系数。
Returns:
- numpy array: 训练得到的权重。
"""
X = normalize(X) # 归一化数据
m, n = X.shape
weights = np.zeros(n)
for _ in range(iterations):
z = np.dot(X, weights)
# 随机选择一个小批量
indices = np.random.choice(m, batch_size, replace=False)
X_batch = X[indices]
y_batch = y[indices]
# 计算预测和梯度
z = np.dot(X_batch, weights)
h = sigmoid(z)
gradient = np.dot(X.T, (h - y)) / m
gradient = np.dot(X_batch.T, (h - y_batch)) / batch_size + lambda_ * weights
weights -= learning_rate * gradient
return weights
def predict_logreg(inX, weights):
@@ -65,7 +77,6 @@ def predict_logreg(inX, weights):
probability = sigmoid(np.dot(inX, weights))
return 1 if probability >= 0.5 else 0
# 这里也写自己的代码实现
def load_data(filepath):
"""
从文件中加载数据,若不自行正确实现,则无法通过评测,**不记录成绩**。
@@ -93,16 +104,7 @@ if __name__ == "__main__":
X_test, y_test = load_data("./data/horse-colic.test")
# 训练对率回归模型
weights = train_logreg(X_train, y_train, learning_rate=0.01, iterations=1000)
# 测试单个数据
y_pred = predict_logreg(X_test[11], weights)
print(f"预测结果: {y_pred}, 实际结果: {y_test[11]}")
# 加载测试集
X_test, y_test = load_data("./data/horse-colic.test")
# 训练对率回归模型
weights = train_logreg(X_train, y_train, learning_rate=0.01, iterations=1000)
weights = train_logreg(X_train, y_train, learning_rate=0.01, iterations=1000, batch_size=32, lambda_=0.01)
# 测试单个数据
y_pred = predict_logreg(X_test[11], weights)